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y^2+9y-100=0
a = 1; b = 9; c = -100;
Δ = b2-4ac
Δ = 92-4·1·(-100)
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{481}}{2*1}=\frac{-9-\sqrt{481}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{481}}{2*1}=\frac{-9+\sqrt{481}}{2} $
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